# 2019 WAEC GCE MATHEMATICS VERIFIED OBJ AND ESSAY | HOW TO GET MATHEMATICS ANSWER EXPO

**WAEC GCE MATHS ANSWER**

__MATHS-OBJ
__1BBDCCBCBAA

11BCBDCDBDDB

21BCBDCBAACA

31AABBDABCCB

41BBBDBCBCDB

**Completed.**

__MATHS-Theory
__bonus.

**(10a)
Loan borrowed = 80/100 × 350,000
=280,000
Amount paid to the bank after 8 years = P + I
= P + PRT/100
=280000 + 280000×7×8/100
=280,000 + 156,800
Amount = #436,800**

Total cost of house to the man = #350,000 + Interest

= #350,000 + 156,800

= #506,800

(10b)

Percentage increase in cost of house = 506,800 – 350,000 × 100%

= 156,800/350,000 × 100%

= 44.8%

(10c)

Percentage loss = loss/cost price × 100%

=(506,800 + 10,000) – 460,000/(506,800 + 10,000) × 100%

= 516,800 – 460,000/516,800 × 100%

56,800/516,800 × 100%

= 0.1099 × 100%

= 10.99%

(10)

Click here the image

=================================

(12)

Draw the diagram

x² = 20² + 8² – 2x 20 x 8 x Cos 50º

x² = 400 + 64 – 320 x 0.6427

x² = 464 – 205.7

√x² = √258.3

x = 16.1

x = 16km

(12ai)

TJ = 16km

(12aii)

sinØ/20 = sin50/16

sinØ = 20 x sin 50/16

sinØ 0.9576

Ø = sinˉ¹ 0.9576 = 73.3º

The bearing 90 -73.3 = 16.7º

(12b)

Draw the diagram

y = √12² + 5²

y = √144 + 25

y = √169 = 13

tan Ø = 5/12 = (0.04167)

Ø = tanˉ¹ (0.4167) = 22.6º

Sin Ø = 5/6 + x

Sin 22.6º = 5/6 + x

(0.3843) (6 + x) = 5

2.3058 + 0.3843x = 5

0.3843x = 5-2.3058

0.3843x/0.3843 = 2.6942/0.3943

X = 7.01

X ≈ 7

__
__(12)

CLICK HERE FOR THE IMAGE

=================================

(9i)

DRAW THE DIAGRAM

n (U) = 110

n (P) = 25

n (B) = 45

n (M) = 48

n (Pnm) = 10

n (Bnm) = 8

n (pnBnm) = 5

(9ii)

for biology = 45 = 36

(9iii)

x + 14 + 1 + 5 + 5 + 36 + 3 + 35 = 110

x + 25 + 36 + 38 = 110

x = 110 – 99

x = 11

(9b)

15 = 22 + 18 + 2 x 1 + 10 +20/5

15 x 5 = 40 + 2x + 31

45 = 71 + 2x

45 – 71 + 2x

2x/2 = -26/2

X = 13

22, 18, 2x + 1, 10 , 20

For 2x (-B) +1 = -26 +1 = -25

22, 18, -25, 10, 20

-25, 10, 18, 20, 22

The media is 18

(9)

CLICK HERE FOR THE IMAGE

=====================================

(13)

Click here the image

=====================================

=====================================

(5a)

Obtuse Reflex

<MOP + <MOP = 360(angle at a point)

Obtuse <MOP + 196° = 360°

Obtuse <MOP = 360 – 196

= 164°

OMP + OPM + Obtuse MOP = 180°(<s in a triangle)

But OMP = OPM = x(radius of the circle and hence base angles are the same)

2x + 164 = 180

2x = 180 – 164

2x = 16°

X = 16/2 = 8°

Also MNP = 1/2×obtuseMOP

= 1/2 × 164°

= 82°

Now; MNP + NMP + NPM = 180° (<s in a triangle)

82 + (52+8) + (m+8) = 180°

m + 150 = 180°

M = 180 – 150

M = 30°

=====================================

=====================================

=====================================

(3a)

3√3/2 – 4√2/3 – √24

=3√3/2 – 4√2/√3 -√6*4

=(3√3/√2 × √2/√2) – (4√2/√3 × √3/√3) – 2√6

=3√6/2 – 4√6/3 – 2√6

=(3/2 – 4/3 – 2)√6

=(9 – 8 – 12)√6

= -11/6√6

(3bi)

prob(only one passes) = m passes and N fails or M fails and N passes

Prob (M passes) = 2/3; prob(M fails) = 1 – 2/3 = 1/3

Prob(N passes) = 4/5; prob(N fails) = 1 – 4/5 = 1/5

Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)

= 2/15 + 4/15

= 6/15

= 2/15

(3bii)

prob(at least one passes) = prob(only one passes) + prob(both parties)

= 2/5 + (2/3 × 4/5)

= 2/5 + 8/15

= 6/15 + 8/15

= 14/15

(3)

Click here

=====================================

(1a)

Tabulate

X|2|3|4|5|7|

2|4|6|2|6|

3|6|1|7|5|

5|2|7|1|3|

7|6|5|3|1|

(1bi)

n=7,i;e 3 (*)7=5

(1bii)

n(*)n=1, n=3

(1)

Click here

=====================================

(2a)

Given; slant height l = 18.7cm

Diameter, d = 24cm

π = 22/7

But, Curved surface area of cone = πrl

=π(d/2)l

= 22/7 × 24/2 × 18.7

=9873.6/14 = 705cm²

(2b)

128^x × 2/16^(1-x) = 8⅔x

= 2^7x × 2/2^4(1-x) = 2³(⅔x)

= 2^7x + 1/2^4(1-x) = 2^2x

Cross multiply

2^4(1 – x) + 2x = 2^7x + 1

4(1 – x) + 2x = 7x + 1

4 – 4x + 2x = 7x + 1

4 – 2x = 7x + 1

9x = 3

X = 3/9 = 1/3

(2)

CLICK HERE

Categories: Waec gce runs free exam expo, Waec runs 2020 expo answer supply

**SELECT EXAM YOU WILL WRITE AND CLICK ON IT**

***INVITE YOUR FRIENDS TO OUR WEBSITE***