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2019 NECO GCE PHYSICS PRACTICAL ANSWER

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PHYSIC-PRACTICALS-ANSWERS

(1ai -1aiv)
S/N|M(g)|Real values of b(cm)|Converted values of b(cm)| Real Value of d(cm)| Converted values of d(cm)| N = b/d
1 |20 |5.30|26.50|12.9|64.5|0.41|
2 |40 |8.0 |40.0 |10 |50.0|0.80|
3 |60 |9.9 |49.5 |8.3|41.5|1.20|
4 |80 |11.0|55.0 |7.0|35.0|1.50|
5 |100|12.1|60.5 |6.0|30.0|2.0|

(1bi)
(i)the total upward force must balance the downword
(ii) the algebraic sum of all forces act on the body must be equal to zero

(1bii)
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(1vi)
slope = Y2-Y1/x2-x1
=70-20/1.4-0.4
= 50/1
=50g

(1vi)
(i) I avoid error due to parallel when taking all my reading
(ii)I made sure that the meter rule beconect horizontally before taking my reading

(1a)
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(1)
Graph
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(3ai -3aiv)
S/N|R(ohms)|V(v)|I(A)|1/v(A/v)|R-¹(ohm-¹)|
1 | 1.0|1.21|1.80|1.49|1.00
2 | 2.0|1.50|1.50|1.00|0.50
3 | 3.0|1.64|1.36|0.83|0.33
4 | 4.0|1.72|1.29|0.75|0.25
5 | 5.0|1.76|1.23|0.70|0.20

(3av)
PLOT THE GRAPH

(3avi)
Slope = ΔA/V / ΔR-¹
= 1.28 – 0.80/ 0.80 – 0.30
= 0.48/0.50
= 0.96

Intercept (c) = 0.50

(3avii)
(i) I would ensure I made tight connection before taking my reading.
(ii) I would ensure I noted zero error on the voltmeter and Ammeter

(3bi)
Potential difference is the work done in moving a unit charge from a point in electric field to another. It has the unit of Volt.
V = work done/charge

(3bii)
r = 0.5ohms
I = 1.2A
R = ?
E = 3v
E = I(R+r)
E = IR + Ir
E – Ir = IR
R = E – Ir/I
= 3 – 1.2 × 0.5/1 .2
= 3 – 0.6/1.2
R = 2.4/1.2
R = 2 ohms

(3a)
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(3b)
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(3)
GRAPH
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